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pole inductance | 29 comments (29 topical, editorial)

Re: pole inductance (3.00 / 0) (#11)
by bob g on Fri May 16th, 2008 at 09:24:16 AM MST
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a bifilar wound resistor has no inductance i am told

a bifilar wound iron cored inductor also has no inductance i am told as well.

yes each coil has its own inductance, but when they are wound together the effect is no inductance collectively? seperately yes, but together no?

i am not trying to get rid of the coil inductance, however i am trying to reduce the pole reactance, armature reaction

i am looking at having to rewind a stator anyway, perhaps the answer will come from just doing a test.

my hope was to get an understanding of the interaction of the two coils
carpel tunnel is no fun when it come to rewinding a stator.
but no pain, no gain i guess :)

thanks guys

bob g

[ Parent ]

Re: pole inductance (3.00 / 0) (#16)
by finnsawyer on Sat May 17th, 2008 at 08:33:39 AM MST
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Your two examples involve the reaction of the 'coils' to an external voltage source. Since the coils are wound in opposite directions the flux created by one coil opposes the flux created by the other coil, hence no measurable inductance, although each coil still has its own inductance. In the case of the alternator the time varying flux is already there, and it will induce a voltage in each coil. When the two coils are connected in some manner and a net current flows out, the principle of the conservation of energy kicks in. Since power or energy is coming out of the coils an equal or greater amount of power must be supplied at the axle of the rotor. The only way that power can be transmitted to the coils is through the magnetic flux. The process always acts to retard the motion of the rotor whether the current is 1 milliamp or 10 amps. I mention the milliamp current because you could conceivably connect the two coils together such that the voltages oppose each other. In that case, due to imperfect winding you could have a small current flow in a loop through the coils. No matter which direction that small current flows the axle must supply greater power to the rotor due to the power dissipated in the coils. This is not a "free lunch" universe. The energy equation must always balance.
GeoM
[ Parent ]

Re: pole inductance (3.00 / 0) (#17)
by bob g on Sat May 17th, 2008 at 09:32:12 AM MST
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Geo:

at least as far as i am concerned, i fully understand that there is no free lunch
as a matter of fact you cannot even break even! :)

i have been at this long enough to understand the basic rules of nature/physics/ohms law/etc...

that being if i want more power output (useable), i will have to do one of two (at least) things.

either input more power (mechanical), or
improve the efficiency of the alternator (electrically)

what i am after is a reduction in some of the losses within the machine i am working with, and alter the way it performs its function in a much different application than it was originally designed for.

not much different than the thinking behind all the other conversions on the forum,
but not specifically targeted for windpower use.
lessons learned from the process might very well have broader application for the diy'er wind generators,, who knows until you ask and experiment.

thanks

bob g

[ Parent ]

Re: pole inductance (3.00 / 0) (#22)
by finnsawyer on Sun May 18th, 2008 at 08:38:42 AM MST
(User Info)

Since it's more power or shall we say more bang for your magnet dollar, I suggest you read my diary if you haven't already. I present arguments for a single phase design that should output more power than a three phase with the same number of identical magnets. The reason is fairly simple. It involves more coils for the same number of magnets with a larger rotor. Since the coils move past the magnets faster you get more voltage out per coil, which can translate into more power. The link is:

http://www.fieldlines.com/story/2006/4/21/16237/9933

GeoM
[ Parent ]

pole inductance | 29 comments (29 topical, 0 editorial)

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