Go to Otherpower.com Home Page Go to Forcefield Shopping Cart Go to Wondermagnet.com Home Page
Front Page - [Homebrewed Electricity-- (wind) (solar) (hydro) (steam) (controls) (storage) (mechanical)] - Classifieds - Site News
Everything - Newbies - [Remote Living-- (housing) (heat) (light) (water)] - Rants & Opinion - Diaries - Our Products
Beginner question about stall and such | 14 comments (14 topical, editorial)
Re: Beginner question about stall and such (3.00 / 0) (#6)
by CmeBREW (smke833f@hotmail.com) on Thu Jun 5th, 2008 at 02:23:12 PM MST
(User Info)

Those are all excellent answers!

Those certainly are the main causes of stall in windmills.  I don't mean to complicate this any more, but it seems to me that some , at times, also refer to the aeronautical aspect of the blades themselves "stalling" in low rpm rotation because the airfoil shape (curved backside)of the blades cannot get to the point of acheiving 'Lift', because of being 'held back' from picking up enough rpm from the reasons just described from everyone's answers.  

This might be really saying the same thing.  I am still learning myself on this, but is it possible, in a rare occurance, that stall could also be caused by the blades themselves, apart from the stator or line resistance??
Perhaps someone who knows could comment?

-Woof: You might consider putting this thread in the FAQ section for windmills in general because it is good??.



Re: Beginner question about stall and such (3.00 / 0) (#7)
by Flux on Fri Jun 6th, 2008 at 01:18:01 AM MST
(User Info)

Stall is exactly as you suggest, it is the aerodynamic failure to develop lift on an aerofoil with too large an angle of attack.

I had never thought anyone would consider it to be anything else. There is nothing in an alternator, line resistance or anything else that causes the phenomena.

The only reason why alternators and line resistance come into this is that they determine the blade input power and that decides the tip speed ratio of the blade. When the tip speed ratio falls well below the ideal the angle of attack becomes too great and the blade stalls.

All you are doing is trading electrical efficiency to keep the blade efficiency high enough to avoid serious stall. Unless you devise a loading that keeps the blade rotational speed in step with wind speed you are changing the tsr.

Flux

[ Parent ]



Re: Beginner question about stall and such (3.00 / 0) (#8)
by JW1111 on Fri Jun 6th, 2008 at 08:04:17 AM MST
(User Info)

 I had always thought that blade pitch creates turblulence at high rotation and that was the definition of stall.  But basically every response here started talking about current and voltage.  This paragraph suggests that load is directly the cause of stall:

"The tsr falls very rapidly with load and you will soon come on to the peak of the power curve. As you load more you fall below optimum and if you get things right you should just be approaching stall at the time you need to furl to protect the alternator."

I guess it is over my head and you probly dont begin to understand it completely until you get in to buiding motors. Thanks alot.

[ Parent ]



Re: Beginner question about stall and such (3.00 / 0) (#9)
by finnsawyer on Fri Jun 6th, 2008 at 08:45:45 AM MST
(User Info)

I've been debating whether to wade in on this.  My suggestion is to draw a couple of graphs.  Assume the alternator curve is linear (a straight line) and puts out zero watts  at 12 mph and 1,000 watts at 30 mph.  Let the wind turbine, on the other, obey the cubic law and also puts out 1,000 watts at 30 mph.  At 15 mph it puts out only 125 watts, the cubic behavior.  That's all it can do at each wind speed.  Overlay the two curves and it becomes obvious that for wind speeds above 14 mph the turbine will be severely stalled.  You can reduce the slope of the alternator by adding external resistance to reduce stall to have it occur at a greater wind speed, or not at all.  But you pay a price.  A proportion of the power generated is lost as heat in the external resistor.

Another way to reduce or eliminate the stall issue is to increase the air gap in the alternator.  In that case the slope remains the same and the entire alternator curve moves to the right.  In that case you could potentially eliminate stall, but you would probably like the alternator curve to just touch the turbine curve at the point of furling.  To my eye (I happen to have this case graphed) cut-in would then be at 15 mph and furling at 24 mph.  Maximum power looks to be about 500 watts.  You do, of course, lose all power generation for wind speeds below 15 mph.  So, you pay another kind of price.
GeoM
[ Parent ]



Beginner question about stall and such | 14 comments (14 topical, 0 editorial)

Menu
· create account
· How to use the board
· FAQs
· search the board
· Google search the board
· Old Otherpower Board

Login
Make a new account
Username:
Password:

Powered by Scoop
You must be a registered user to post here. It's easy and free, and the link is on the upper right side of your page.
All trademarks and copyrights on this page are owned by their respective companies. Postings are owned by the poster, but may be deleted or moved at the ADMIN's sole discretion. The Rest © 2003 Forcefield.
You can Email the board ADMIN here. PLEASE include the username you signed up with!