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Beginner question about stall and such | 14 comments (14 topical, 0 editorial)
Re: Beginner question about stall and such (3.00 / 0) (#9)
by finnsawyer on Fri Jun 6th, 2008 at 08:45:45 AM MST
(User Info)

I've been debating whether to wade in on this.  My suggestion is to draw a couple of graphs.  Assume the alternator curve is linear (a straight line) and puts out zero watts  at 12 mph and 1,000 watts at 30 mph.  Let the wind turbine, on the other, obey the cubic law and also puts out 1,000 watts at 30 mph.  At 15 mph it puts out only 125 watts, the cubic behavior.  That's all it can do at each wind speed.  Overlay the two curves and it becomes obvious that for wind speeds above 14 mph the turbine will be severely stalled.  You can reduce the slope of the alternator by adding external resistance to reduce stall to have it occur at a greater wind speed, or not at all.  But you pay a price.  A proportion of the power generated is lost as heat in the external resistor.

Another way to reduce or eliminate the stall issue is to increase the air gap in the alternator.  In that case the slope remains the same and the entire alternator curve moves to the right.  In that case you could potentially eliminate stall, but you would probably like the alternator curve to just touch the turbine curve at the point of furling.  To my eye (I happen to have this case graphed) cut-in would then be at 15 mph and furling at 24 mph.  Maximum power looks to be about 500 watts.  You do, of course, lose all power generation for wind speeds below 15 mph.  So, you pay another kind of price.
GeoM
[ Parent ]



Beginner question about stall and such | 14 comments (14 topical, 0 editorial)

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