If you dug a deeep hole (say, 90' deep) you would increase (substantially) the pressure of your water flow and increase your yield. With a mere 90' deep hole, you now have 100' head - or 10 times your output power (neglecting losses)
If you happen to live really high up say on a mountain......
(grin)
I suppose since the water is traveling three times faster it's going to give the waterwheel three times the momentum too..[ Parent ]
Maybe we had different physics classes.----------------------------- Go Huskers![ Parent ]
where d is the distance the object falls g is the acceleration due to gravity t is the time considered t² is t times t or t-squared gt²/2 is g times t-squared divided by 2
so 75 feet = (32.17 feet/seconds²)t²/2
(32.17 feet/seconds²)t² = 150 feet t² = 150 feet / 32.17 feet/seconds² t² = 4.6627293 seconds² t = 2.1593354 seconds
100 feet = (32.17 feet/seconds²)t²/2
(32.17 feet/seconds²)t² = 200 feet t² = 200 feet / 32.17 feet/seconds² t² = 6.116208 seconds² t = 2.47309683 seconds
time to fall 100 feet will be square root of ten times as long as the time to fall 10 feet.
energy is 1/2 Kg (m/s)^2
gravitational potential energy is mgh.
[bastardization] gravitational potential power would be (kilograms/second)x(9.8m/s^2)x(height in meters)[ Parent ]
I have shown that the power for 100 foot drop is not 10 times more than for a 10 foot drop. Are you arguing about the math or the whole concept in general?----------------------------- Go Huskers![ Parent ]
Rgds
Damon [ Parent ]
If i drop a 10 Kg ball one meter, just before it touches the ground, it's moving 4.427 meters per second and it has 98 joules of kinetic energy.
If i drop a 10 Kg ball ten meters, just before it touches the ground, it's moving 14 meters per second and it has 980 joules of kinetic energy.
If i drop [one] 10 Kg ball per second, then i have an average energy dissipated at the bottom of 98 watts, and 980 watts respectively.
The definition of work is Fd force x distance.
ask yourself where did the energy go, it is obvious it takes 10 times the energy to lift that water 10X height. [ Parent ]
Horsepower is a unit of power, not energy. Pound-force per foot is the relative unit of energy.----------------------------- Go Huskers![ Parent ]
I am not mixing up energy and power
energy is mgh power is mgh/seconds
one thousand kilograms of water falling 100 meters is 980,000 joules.
I don't care how long it takes to fall.
you can figure the math out.
100. feet / 2.47309683 seconds = 40.435133 feet / second [average speed!] 17. 333 pounds / second * 40.435133 feet / second = 700 foot-pounds per second, which is also 1.27 horsepower.
If the energy didn't go anywhere, then it should work backwards.
700 foot pounds/second will lift 7 pounds of water 100 feet per second.
you started with 17.33 pounds per second.
KISS 17.33 pound/second x 100 feet. = 1733 foot pounds per second or 3.15 horse power.[ Parent ]
Piss you off? Please. If pointing out the facts piss you off then so be it.----------------------------- Go Huskers![ Parent ]
We're not dropping a given mass of water 100 feet.
We've got a continuous column of water, 100 feet high.
The PRESSURE at the bottom of a 100' column of water, times the flow, not the kinetic energy of a unit of water dropped 100' and being allowed to accelerate.
Yes, I started out tongue-in-cheek, just like the OP.[ Parent ]
Furthermore, you calculated average velocity, a worthless number, the RMS velocity would be a better number.
force x distance/time = power. mass x gravitational acceleration x distance[height] / time = power
state your math [ Parent ]
