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hydro plant project question | 7 comments (7 topical, editorial)
Re: hydro plant project question (3.00 / 0) (#1)
by dnix71 (yahoo.com 'dnix71') on Mon Aug 18th, 2008 at 12:04:16 PM MST
(User Info)

Your PMG needs to turn 250 rpm to put out 23 kw/h. As long as the mechanical power in exceeds that (minus gear box losses) then you would get somewhere near 20kw/h out.

Is there an advantage to using a gearbox instead of a reducing v-belt pulleys?



Re: hydro plant project question (3.00 / 0) (#2)
by alibaba on Mon Aug 18th, 2008 at 01:01:19 PM MST
(User Info)

i will be using a gear box in this project. what i can't understand though is : if i achieve the 250rpm with a gear box, will there be enough torque to turn the generator and achieve the 20+kw/h. i don't understand how a project can be calculated at 23kw and still i cann't produce them effectively..

[ Parent ]


Re: hydro plant project question (3.00 / 0) (#3)
by TomW on Mon Aug 18th, 2008 at 01:28:23 PM MST
(User Info)

al;

Well, thats how "calculating" and "doing" differ, I guess. Might be worthwhile to take a step or three back and see if you can reproduce the values used originally.

Things like head, flow volume, etcetera.

It could simply be that some prior "expert" either miscalculated or was not much of an "expert"

Quoting like you did leads me to believe that person was inexperienced.

I am no expert in anything but that looks like something a college professor would write up rather than saying "23KW of energy is available".

Its your baby so do what suits you.

Tom

"Education consists mainly of what we have unlearned."--Mark Twain
[ Parent ]



Re: hydro plant project question (3.00 / 0) (#4)
by Flux on Mon Aug 18th, 2008 at 01:28:30 PM MST
(User Info)

Power is torque x speed. If your torque for 23kW is 2280Nm at 100 rpm the generator will require 2280 x 100/250 Nm to produce 23kW.

Torque is decided by the speed for a given power. Each stage of conversion is less than perfect so you will loose a little in the gearbox so your input to the generator may be down to 22kW. Efficiency of 93% for a 20kW alternator is good going if you can manage it.

How accurate the 23kW calculation is is another matter I can only take that as given.

Flux

[ Parent ]



Re: hydro plant project question (3.00 / 0) (#5)
by alibaba on Mon Aug 18th, 2008 at 01:40:46 PM MST
(User Info)

2000Nm at 100 rpm makes 20kw...so does 800Nm at 250 rpm..so no change due to gear ratio..


[ Parent ]


Re: hydro plant project question (3.00 / 0) (#7)
by Flux on Tue Aug 19th, 2008 at 11:14:54 AM MST
(User Info)

" i don't understand how a project can be calculated at 23kw and still i cann't produce them effectively.."

Can you explain what that is meant to mean?

Have you tried this and found that you can't get near the 20kW or is just some speculation where you are still confused about the issue of changing torque with speed.

As I said before I can only take your figures for the predicted 23kW. If you really have 23kW available at 100 rpm then you have 23kW available at 250 rpm with reduced torque.

As I see it from your original statement you have 2000Nm at 100 rpm ,if so you have 20kW. If you mean a static torque of 2000Nm and a speed of 100rpm then you don't have the details to calculate power.

Unless you can explain properly what you have and  what you are bothered about there is little hope of help.

Flux

[ Parent ]



hydro plant project question | 7 comments (7 topical, 0 editorial)

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