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The mill is up and running | 17 comments (17 topical, editorial)

Re: The mill is up and running (3.00 / 0) (#9)
by wooferhound (tim((NoSpamAt))wooferhound.com) on Fri Aug 22nd, 2008 at 11:44:33 AM MST
(User Info) http://wooferhound.com

Are you running your power through a Bridge Rectifier before going to the Battery ?

W o o f -={(

Re: The mill is up and running (3.00 / 0) (#10)
by kurt on Fri Aug 22nd, 2008 at 05:04:59 PM MST
(User Info)

it is a 30v amatek dc pm motor woof all that is needed is a single diode although a bridge will work wired properly.....

http://www.reresource.org/

IRC
[ Parent ]

Re: The mill is up and running (3.00 / 0) (#11)
by wooferhound (tim((NoSpamAt))wooferhound.com) on Fri Aug 22nd, 2008 at 07:00:28 PM MST
(User Info) http://wooferhound.com

Just making sure that he has some kind of diode on there

W o o f -={(

[ Parent ]

Re: The mill is up and running (3.00 / 0) (#13)
by bend1 on Fri Aug 22nd, 2008 at 08:26:56 PM MST
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yeah i have a diode across the mill output wire. thanks

[ Parent ]

Re: The mill is up and running (3.00 / 0) (#14)
by TomW on Fri Aug 22nd, 2008 at 09:15:02 PM MST
(User Info)

bend;
yeah i have a diode across the mill output wire.

I hope you meant "in series with" because if the diode connected between the 2 output leads it won't work.

Tom

"Education consists mainly of what we have unlearned."--Mark Twain
[ Parent ]

Re: The mill is up and running (3.00 / 0) (#15)
by bend1 on Sat Aug 23rd, 2008 at 07:17:26 AM MST
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No its not in series just across one leg. Everything was working I just did not have any current draw from the mill with the battery connected. Because the output of the mill was low is what I was told. When I removed the battey and replaced it with a resistive load then I had current flow from the mill. And all was well.

[ Parent ]

Re: The mill is up and running (3.00 / 0) (#16)
by TomW on Sat Aug 23rd, 2008 at 07:56:11 AM MST
(User Info)

bend;

I am not tracking you at all. Maybe its me, but your terminology is a bit non standard.

To me, if I put a component [your diode] "across" another component [your generator]it means it is in parallel with the other component.

If you put a diode "across" leads on the generator it is a half wave short. This may appear to work into a resistance but I assure you it is not working "right"

Just trying to understand. Maybe pop into IRC where these things get sorted quickly.

Tom

"Education consists mainly of what we have unlearned."--Mark Twain
[ Parent ]

Re: The mill is up and running (3.00 / 0) (#17)
by bend1 on Sat Aug 23rd, 2008 at 10:54:26 AM MST
(User Info)

It is connected between the positive wire of the mill and the other side is connected to the terminal block that goes to the battery it is a (blocking diode)allowing the voltage/current of the mill to pass to the battery but not allow the batttery voltage/current to flow to the mill and power it.

[ Parent ]

The mill is up and running | 17 comments (17 topical, 0 editorial)

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