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determining test coil load


By electrondady1, Section Homebrewed Electricity
Posted on Mon Jan 9th, 2006 at 08:59:41 PM MST
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in the case of a 32 pole three phase rotor in order to produce battery charging voltage (14 v dc) 14vdc over 1.4 rectifer =10vac. 10vac over 1.7 for three phase star = 5.8 per phase. 5.8vac over 8 coils = .73vac per coil. my initial test coil produced 1.4 volts at my desired rpm 1.4 x 8 x 1.7 x 1.4 =26.65vdc this is i beleave what is refered to as open voltage and has little to do with what the genni could produce when confronted with a load. in order to get insight into what that might be, the test coil must be run with a load. i have been unable to determine how an appropriate test coil load is chosen.( a 1 ohm resistor , 1.5 ohm resistor . a small 12v bulb, on one post "commanda" stated any resistor that pulls the open voltage down by ten percent ) when i measured 1.4 volts on my test coil i thought perhaps i could run two conductors in hand , reducing resistance but still achieving a charging voltage. but i remembered that voltage drops under load. any comments? any one?
determining test coil load | 3 comments (3 topical, 0 editorial)

Re: determining test coil load (3.00 / 0) (#1)
by willib (willibur at comcast dot net) on Mon Jan 9th, 2006 at 06:43:15 PM MST
(User Info) http://www.njwind.com/webcam.html#

here is what i do.
Mult num. of coils per phase by voltage at the desired speed.(scope reading)
for me this was 6 * 4 = 24V Peak ---- at about 280 rpm.
http://www.otherpower.com/images/scimages/2965/svdvt_rpm_per_volt.jpg
divide 24 by sqrt(2) to get the RMS voltage per phase = 16.97V
mult 16.97 by sqrt(3) to get the three phase " star" voltage output of the gen.= 29.4V
At 150 rpm i would expect 14.6V..
Carpe Ventum (seize the wind)


Re: determining test coil load (3.00 / 0) (#2)
by willib (willibur at comcast dot net) on Mon Jan 9th, 2006 at 07:09:25 PM MST
(User Info) http://www.njwind.com/webcam.html#

oh , just last night  i hooked the coil directly to to an ammeter  through a bridge rectifier ,so i was measuring dc Amps , got 3A out of it..
the one i used was the triple wound coil btw.
Carpe Ventum (seize the wind)


Re: determining test coil load (3.00 / 0) (#3)
by Flux on Tue Jan 10th, 2006 at 02:47:51 AM MST
(User Info)

I have never got any useful prediction of output by loading a coil. It ought to work but as I have found a better way I have never bothered to struggle with it.

I use the test coil to determine cut in speed as you have done. I then accurately measure the coil resistance and from that I find the winding resistance. knowing the number of coils in series per phase and for star there are 2 phases in series.

At the speed you want to know the power you work out the open circuit voltage, subtract the battery voltage to get the internal voltdrop then divide by the resistance to find the current.

Say you have a cut in at 12v of 100 rpm and you want to know the current at 400 rpm.

At 400 rpm you generate 48v, subtract battery volts leaves you with 36. Divide this by the resistance to find the current into the battery.

This always gives an over optimistic answer and to make it work properly I have to multiply the measured resistance by 1.3 ( don't ask why but it works).

This does assume that you can accurately measure resistance and most people can't.

If you load your test coil with a resistor that halves the voltage then the coil resistance should be equal to the resistor. Unless you have the exact resistor or can measure a variable one it doesn't help.

You should be able to work it out from the drop with any suitable known resistance but most of the commercial low resistors are very nominal in their value, that and connection resistance at low levels may be why I have never got sensible results.

Learn to make accurate resistance measurements by the volt drop method , measure the coil resistance and you will be ok.

Flux

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determining test coil load | 3 comments (3 topical, 0 editorial)
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