Abyss (and all),
You wrote in another thread:
"If you intend to run the battery at float mostly and use it for standby power, then 13.6-13.8v will be just fine. My 7Ah 12v SLA used to draw about 30mA once charged to stay at float."
The statement above made me think about something I really never understood very well, and still do not (thus the ? ).
Does this float voltage and 30ma current specifically, indicate or is a factor of, battery internal resistance?
Doesn't lengthening the battery string to increase system voltage also increase internal resistance?
I know adding resistors in series in does this and have made specific resistance circuits doing this, such as precise time divisions on a 555.
Would this be a precise way to cipher this internal battery resistance?
Say 13.8 X .03 amp = 0.414 watts
Can we then determine the battery(s) internal resistance from that wattage number, and what would the math be for that if possible?
Would this be a better way to measure the actual battery state of charge, by adding the resistance factor unique to the battery in question?
Does rising or falling internal battery resistance an indicator of battery life in any way? (other than open or shorted)
Thanks,
[moviequote]
"Oh, Deep Thought (abyss) do you have the answer to the question?"
"Yes, but you're not going to like it".
[/moviequote]
