My intended use is to power a 16" saw blade for a mini sawmill. I won't have 3 faze power available, and plan to plug it into a 240V, 30 amp dryer plugin. (No doubt it will be down to the rated 230V or less by the time it gets through the cable to the outdoors.)
The motor is a Baldor that had the following specs before a previous owner burnt it out with a seized air compressor:
Slots: 36
Rotor diameter: about 3-1/4"
Stator length: about 4-1/4"
RPM: 3450
HP: 7.5 DP
Volts: 208-230/460
Amps: 19-18/9
Efficiency: 85.5%
PF: 91%
Hz: 60
Phases: 3
Class: B
Service Factor: 1.15
40 degrees C ambient continuous
Cat#: M32-19T
Spec: 36B01-194
Frame: 184T
Windings: 6 coils per faze
A: 3-16,2-17,1-18 (in series), and 36-19,35-20,34-21, with 22 windings per coil
B: 4-27,5-26,6-25, and 7-24,8-23,9-22, like A
C: 10-33,11-32,12-31, and 13-30,14-29,15-28
The pairs of 3 coils on each faze are connected in parallel for 240 V (66 winds per faze) and series for 480 V (132 winds per faze).
If it is of any significance, the wire throughout was 2 strands of #21 and 2 of #22, the 4 strands in parallel. I plan to use beefier wire with less strands. That should give the same amount of copper with less insulation volume in the slots, leaving a bit of elbow room, eg for starting windings. (I actually counted 88 wires in one coil, 87 in another (assumed I missed one or it was burned off), and divided by 4 to get 22 turns per coil)
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First, I'm not clear on how voltage is measured in 3 faze wye/star systems: if it's "230V", is that from each faze to common, or from one faze to another?
Then, I'm not sure how the 3-faze current is worked out. One can calculate what the single faze full load current should be as:
The motor power as watts = 7.5 HP * 746.7 W/HP = 5600 W
Watts = E*I*Efficiency, thus I = Watts/(E*Efficiency)
or in this case:
I = 5600/(230*.855) = 28.5 Amps
(Obviously no problem at all for a 30 amp dryer outlet! I'd have to use an extra 25' or so of cable to use the 40A kitchen stove outlet, and it's not very accessible.)
If one assumes the 3-faze rated current of 18 amps is multiplied by 1.5 for single faze, we get 27 amps, which is close but not quite right. (Closer than using square root of 2 or sine of 60 degrees, though!)
Let's just go with the 1.5 anyway. If we want 1.5 * the 3-faze current, do we use 2/3 of the windings between two fazes, ie 2/3 of 66*2 = 2/3 of 132 = 88 turns? That's probably wrong. How about 66 turns from one faze and half of each of the other 2 (33 turns) = 99 turns? That's probably wrong too. My gut feeling says to use about 110 turns. That's probably wrong too.
Then, are these turns to be distributed equally over the 18 coils? For 110 turns, that would be 6.11 turns per coil, if they're all in series. Or do we distribute them over, say, 9 or 12 coils, leaving slots for 9 or 6 free coils at 90/270 degrees just for the starting windings?
Then we get to the starting windings: how many, how thick wire, and do we put them over the main windings or use free slots?
Finally, the starting stuff - I presume a centrifugal switch at say 1200 RPM, but how big should the capacitor be in uFarads, and what other ratings does it need?
You'd think these things, while not trivial, aren't exactly rocket science. Surely, for example, there is a single ratio for the number of winds for single faze operation versus the number for 3 faze at a given voltage, current rating and frequency. But in the absence of any such general info, guidelines or formulas seeming to exist, it's no wonder the guys in the motor repair shops back off like it was a hive of bees when you start asking about modifiying a motor!
Maybe I knew some of this stuff after my power electrical course at BCIT in 1974, but somehow I can't seem to remember any of those sorts of details.
--Craig