I've also read that current is determined by the size of the wire, but that's as much as I know.
In a battery-charging application with a rectified alternator, neglecting capacitive and inductive effects (which are minor compared to resistance in the designs and at the frequencies we're using), current is determined by:
- the generated voltage
- minus the sum of the battery charge voltage and the diode voltage drops (two diodes in series)
- divided by the resistance.
Most of the resistance is the resistance of the wires in the coils. (The other major components are the resistance of the wiring from the mill to the battery - which is enough to matter a lot - and the internal resistance of the battery itself - which is small unless you've just been charging or discharging heavily.)
Current is limited in two ways:
- The amount you can drive at a given RPM is directly limited by the resistances.
- The amount you WANT to drive is limited by the heating of the wire. (You don't want to burn up your mill, so you set it to furl before it is driving so much current that it fries.)
More turns of thicker wire, higher voltage, higher resistance, and lower current. Fewer turns of thinner wire, lower voltage, lower resistance, higher current. Figuring the curent you'll get at a given RPM is complicated slightly by the fixed voltage of the battery.
What matters for current limiting to avoid burnout is the current density in the metal of the wire. So you can get the same amount of ENERGY (at the alternator output) from a given amount of copper in the alternator, whether it's wound as a lot of turns of thin wire (for high voltage and low current) or a few of thick wire (for low voltage and high current).
(Losses in the transmission wiring go up with the square of the current times the resistance, so you need four times as much copper in the wires to get the same percentage losses at twice the current and half the voltage This means you'd prefer to go with high voltage and low current to keep expenses low. But you have to make this tradeoff by selecting your battery bank voltage.)