" Hear is what i think i know. Blades are 6' so with some research in 10mph wind i am getting 300 rpm at 18 volts 2.9 ohm and 6.9 amps. Is this looking Right?? I am still Not sure??"
If your motor was rated at 90v at 1750 rpm then to reach cut in ( say 13v For a low battery) then it will need to run at 1750 x 13/90 or 250rpm. As a generator the losses work differently and the cut in may be a little over 250rpm but we can't predict any more accurately.
If would seem unlikely that you would see 18v at 300rpm, but it is in the right ball park. You will certainly be above cut in at 300 rpm.
Now I have no idea where the 2.9 ohms and 6.9A come from. Unless you clarify this then there is no point in guessing. If it is the internal resistance of the motor then you will not get a charging current of 6.9A. If it is your dump load resistor value then it is irrelevant to the charging process.
Elsewhere you explained that you were measuring open circuit voltages. If this deliberate and the diode is not connected then these voltages make sense but it is a dangerous thing to do. If you are measuring these voltages before the diode and it is supposedly connected to the battery then there is something wrong.As CmeBREW said, the thing should be clamped to the battery voltage. Somehow you seem unable to explain what you are really measuring.
Open circuit voltage is meaningless beyond cut in and you should not be looking at it.
You say at one point you measured 90v, that will be at 1750rpm or above and is a truly frightening speed for a 6ft prop, it will be more like a helicopter noise.
I realise you are new and are confused by the terminology, but you should be measuring things when the diode is conducting to the battery. Volts are meaningless except for state of battery charge, you need to measure amps.
If you could clarify the resistance and current figures mentioned above it would help us figure out what you are doing.
Flux
