honda stator rotor

[MVIDSMITH]

turbine is 2 inches wide and 12.27 inches in diameter  turns at 220 rpm

supply is a spring that runs at about 120 gpm.

fall is 17 feet  supply pipe is 2 inch plastic

the honda rotor and stator I have are supposed to run about 800 rpm. I will use a 5 1/4 inch pulley on the water wheel and a 2 inch pull on the generator. then we'll go from there.

Output is 3 phase ac.

mark

[Nando]

MARK:

17 FEET *0.3048 = 5.2 METERS.

(120 GPM * 3.78 LITER) / 60 SEC = 7.6 LITER/SEC

12. 27 INCH *2.54 CM / INCH = 31.2 CMS DIAMETER
    
5. 25 DIA / 2 DIA = 2.6 RATIO
   
   

GROSS WATTS = 5.2 METER * 7.6 LITER/SEC * 9.81 GRAVITY = 387.7 Watts

Water Velocity = squarerroot (2 * 5.2 meter * 9.81) = 10.1 meter / sec

Actual RPM at peak power

(Water vel) / 2 = 10.1 / 2 = 5.05 meter / sec = 505 cms / sec

Turbine RPM = ((Water vel) / 2) / ( PI * Turbine diameter) = 505 / ( 3.14 * 31.2 cms)= 5.2 RPS = 5.2 Revo per SEC ) * 60 sec / minute = 309.1 RPM

Turbine RPM * 2.6 ratio = 803 RPM

With that alternator efficiency and the speed multiplier you may get 40 % power out or 387.7 watts * 0.4 = 155 watts, and I am guessing that you may get around 120 watts.

Missing from the equation the pipe lentgh to calculate the water friction losses for lower head.

Regards

Nando

[Nando]

Reducing the Turbine to a diameter that is 2.6 times smaller you will get the direct RPM gaining around 5 to 10 % additional power.

Nando

[MVIDSMITH]

thank you nando. I will let you know how it works out when its up and running.

should be about a week.

[Nando]

Did you finish the work and the turbine working ?.

Nando

[MVIDSMITH]

nozzle took a little longer to design than I thought and I don't have much time to play. I go to school in the mornings 4 days a week and work at the USPS in the afternoon and evenings 6 days a week. I don't have 1 full free day.

I will post pictures and report on the current as soon as its all together.