This is not so simple. Unless you get a milliohmeter with 4 lead Kelvin connection it will not be very accurate at reading the low resistances of the coils you need to be using. Normal multimeters are not much good below 5 ohms. You can measure by the volt and amp method with normal meters.
Assuming you choose coils for the cut in speed you want then for 12 magnets and the common arrangement you will have 9 coils ( 3 per phase).
Two volts ac per coil will get you cut in at your chosen speed at 12v in 3 phase star with rectifier.
If you know the winding resistance R between a pair of output leads ( 6 coils in series) then you can predict the current into the battery at various speeds.
At 3 times cut in speed you will have 36v dc open circuit. You have 24v above battery volts so in theory the current will be 24/R amps. In reality it will be much nearer 24/R*1.3 Amps.
The power lost in the alternator will be three times the loss per phase. Each phase will have a resistance of R/2 ohms. So power lost will be 3*I^2(R/2) watts where I is the rms winding current( using dc battery current will be near enough).
Flux