Hmmm, If Tink comes from an area with predominatly 24v power systems.... his conversion is actually pretty close.
" By my calculations that would consume 1.38amps AC so would be about 6.19amps DC. I may be wrong on my conversion to DC since I've not found an exact ratio between AC and DC. If there is one I'd like to know it.
Tink"
I suspect that is how they think up there.....
1.38A x 110V= 152 watts.
6.19A x 25v = 154 watts.
From this I figure that Tink and the folks up there equate their DC battery draw directly to the wattage of their equipment.
Tink, Tomw is correct. If you take the amps x volts you get watts....AC or DC... But it is interesting how local usage has used this odd idea for rule of thumb calculations.
As a roughy, divide the wattage of your appliance by the nominal battery voltage.... ie 150watt TV/48v or 150W TV/24v will get you the ball park current draw from the batteries in DC to drive the converter and power the device.
In this case the 150watt TV would draw roughly 150w/48v=3 Amps DC or so from a 48v bank For the 24V bank we get 150w/24v = 6 and a bit amps DC from the battery....
This can only ever be rule of thumb stuff, as the SOC of the batteries and the converter efficiency will alter the figures... but should be close enough to work in the ball park.... thats why there is no exact conversion for you to find. (SOC = state of charge... were they 23, 24, 25,or 26vdc at the time?)
Now for some messy queer stuff...(and get ourselves into trouble)
The power factor will change the VA.... but not the wattage....which is odd as watts = VxA, but not in the case of power factor things. The extra amps in the VA as compared to the Watts figure (worked backwards), do not have any in phase voltage attached, and so cannot do any work (read watts). The extra current will appear in your fuses and current meter, and wiring... but not a watt meter.
How the converter deals with this will depend on the topology I guess, and be different for each type. I haven't tested mine in this configuration, so it would be interesting what the DC VxA was compared to the VxA of a poor powerfactor load.... are they far apart or close (less a conversion factor calculated with a resistive load). I suspect apart.... ie the poor power factor device VA figure will be much larger than the DC VxA watts to drive the converter.... but I've messed this PF stuff up before too.
...... anyone tried this sort of thing?
...........oztules