Hello I have two questions that I can't find the answer to.
1. How do you figure the resistance of the alternator on the Blade programs.. Previously someone commented that on a three phase alternator it would be the same as two of the legs in series. That's assuming it is star wound. And if it was Delta wound it would be 1/3rd of the star.
But what about these 10 phase machines or even an off the wall experimental machine?
I have a 12 phase stator, with 6 of those full wave rectifiers, much like the plans that Hugh has. I made it with 70 turns of 16awg wire per coil. The suggestion was made that since it was not made with 15awg wire it would heat up with the extra resistance. Hence I used only 70 turns of 16 awg wire verses the number of turns in the windmill plans. 90 of 15awg I think.. And when the coils were laid in the mold there was so much extra room I just added two more coils.
The simple solution would have been to go buy 15awg, but I used what I had on hand.
Also could the machine have been built with 90 turns of 16awg wire and 12 coils. Wouldn't that have cut down the resistance with the added coils.
I searched this web site and read the help file at Windstuffnow but can not find where this issue is addressed.
2. And a second question if the drop is figured on the trailing edge as the distance from the top of the board why are the wedges for added blade angle put at the front of the blade and not at the back of the blade?
Thank you Smithson