Author Topic: more coil resistance  (Read 1347 times)

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electrondad1

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more coil resistance
« on: October 24, 2004, 12:16:07 PM »
i just checked an awg chart that gave wire dia. and ohms/ft. 14awg is .064" in dia. and 2.5 ohms/ft.  22awg is .025" in dia. and 16.2 ohms/ft. if i run a two strand coil or two single coils of 22awg the cross sectinal area of copper would be about the same as 14awg but hte ohms/ft. would still be much higher at 8.1 . to get the same resistance (currant capacity) as 14 awg  would i need 7 strands or coils?
« Last Edit: October 24, 2004, 12:16:07 PM by (unknown) »

jimovonz

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Re: more coil resistance
« Reply #1 on: October 24, 2004, 12:53:34 PM »
I don't know about your chart but from this one (of the many out there): http://www.microwaves101.com/encyclopedia/AWG.cfm


  1. AWG is 0.064" in diameter, has a cross-sectional area of 3227mils^2 and a resistance of 2.44Ohms/1000ft
  2. AWG is 0.025" in diameter, has a cross-sectional area of 502mills^2 and a resistance of 15.7Ohms/1000ft


From this data you would need 7 x 22AWG conductors to match (actually slightly better) a single 14AWG conductor.

Doubling conductors, halves the resistance.

I'm not sure, but it looks as though you may have confused diameter with cross-sectional area.
« Last Edit: October 24, 2004, 12:53:34 PM by (unknown) »

Flux

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Re: more coil resistance
« Reply #2 on: October 24, 2004, 12:58:25 PM »
Where do you get these crazy figures.


.064 is about 7.5 ohms/1000 yds  ( 3000 ft if you don't use yds over there)


.025 is about 49 ohms/1000 yds.


Half the csa of .064  is about .046.


You need about 6 strands of .025 in parallel to have the same csa as .064.


Flux

« Last Edit: October 24, 2004, 12:58:25 PM by (unknown) »

bill541

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Re: more coil resistance
« Reply #3 on: October 24, 2004, 01:02:59 PM »
My pocket reference shows:


(22AWG 25.3 mil dia.) at .019 Ohms/foot @ 149 deg F.

(14AWG 64 mil dia.) at .00297 Ohms/foot @ 149 deg F.


A quick rule of thumb is any time you double up a wire, this reduces its wire gauge by 3. So a pair of 22 AWG wires is approximatly equal to a 19AWG wire.


A more accurate way of doing this is to add up the circular mils of the wires in parallel. For example the 22AWG wire has an area of 642 circular mils, two of them in parallel have an area of 1284 circular mils which is about equal to a 19AWG wire with an area of 1290 circular mils.


To equal a 14AWG wire (4110 circular mils), you would need 4110/642= 6.4 or say 7 22AWG wires in parallel.


-Bill-

« Last Edit: October 24, 2004, 01:02:59 PM by (unknown) »