Facts! I love them. Thanks for the link. unfortunately I do not believe it's correct. The math is confusing the conversion of Line current to RMS with calculations with three phase power. Rather complex. I will take a stab at a solution.
Three phase Vs DC, what is the True story?
Lets agree 100Vrms = 100VDC, same with current (I), and Power (P).
Why do I want this?
If DC power is power RMS then the peak or RMS currents are not important, plus they get very confusing.
The load whether a resistor or a 3 phase bridge will follow the equations below.
I'm willing to go into the peak currents and such to prove it. Will take a while. Might just be easier to do an experiment. What do you suggest?
Calculation for DC is easy, 400VDC driving a 1200w load.
Current is 3amps.
Now the same thing with 3 phase. Not so easy.
Each phase will have one third of the load or 1200 / 3 = 400w
The phase current will be 400w/400Vrms = 1amp RMS.
The line current will be the sum of the two adjoining phases, the math is
I line = square root 3 * I phase = 1 * 1.73 = 1.73 amps RMS.
Assumption: Wire cost is based on the amount of copper in it.
To compare power transmission with 3 or 2 wires, each solution will have the same copper content.
Given: 3 phase wire impedance is 3 ohms. (We can use resistance to)
For the DC wire we take the third wire split it in half, parallel one each to the two wires. 6 ohms comes from splitting the third wire in half.
So, the DC wires resistance is R = (3 * 6) / (3 + 6) = 2 ohms.
Power loss in the wires. R * I * I = P
DC is 2 ohms * 3 amps ^2 = 18w each wire or 36 watts total.
3 phase is 3 ohms * 1.73 ^2 = 9 w each wire or 27 watts total.
Wire power loss in 3 phase is 75% of the DC (100%).
For very long runs 300 miles, the 60 Hz inductance and capacitance become a bigger problem and DC wins the day. A huge down side to DC is the necessary equipment on the receiving end to convert it back to AC. Not the case here.
How was that? Did I mess up any of the math? Checked it against my book.
Have fun.