Ross....when I said single coil ,I didn't mean a single turn of wire....the coil is 36 turns of,.. I think 1.2mm wire (Attachment Link)
I measured it with a tape..."nothing to fail with EMP"...I don't know what that means???
Ahh. ok. Wasn't clear.
EMP is "Electro-Magnetic Pulse". I was thinking in terms of complex device(s) to boost the output and their susceptibility to damage.
I added a bifilar winding to the top of the coil , to get these results...the big primary was off the scale of 250VAC....but the volts on the other side of the bridge were still low.......The bifilar coil does boost output......
Odd, bifilar windings are generally wound such that they're "non-inductive" - which also means they shouldn't have any appreciable voltage induced in them in the presence of a magnetic field, so I don't see the mechanism by which one will "boost output" at all.
As for your comment that "additional turns = additional resistance = less current"..... well, yes, but lets not forget that if the voltage is so low you get nothing out the bridge, you already have "no current" so even a small current is better than no current
There are basically a few variables. For a given coil that means its number of turns and physical dimension is a constant, you can increase the output voltage by:
* adding additional complete coils in series (in phase)
* increasing the rate of change of the magnetic field
* reducing the load (obviously not a consideration in unloaded coil tests)
Increasing the rate-of-change of the magnetic field could be done by increasing the relative speed of the movement between the coil and magnet, or by making the magnet stronger, or by interspercing additional magnets of alternating N/S alignment, or a combination of the above.
At a theoretical (rather than practical) level, confining the magnetic field into a narrow beam would allow for a substantially higher rate-of-change of flux density and therefore higher voltage, but over a proportionally reduced time, making high voltage pulses. Probably the same *power* output (watt-seconds) and *average* voltage, so I can't see where you get an advantage.