going from wye to delta, you increase amperage by 173%, you decrease voltage to ~57.6%
i would assume that going from wye to IRP will result in an increase of amperage, and a decrease in voltage
same as going from wye to delta, but i am not sure of the factors, it might be a bit different than 173% and 57.6?
bob g
edit: it also occurs to me that it will depend on what you do with the resultant power from each of the IRP groups
if you parallel them, or if you series connect them after rectification
i am guessing here, but if you go IRP (jerry rigged) and connect them in series after rectification
then you will have the same amperage as in wye, but the voltage will be approx 1.73 x the wye phase to phase?
somewhere i remember it listed as ~225% of the voltage of a single phase
got me wondering now if i read that or dreamed it?
bob g