With J1 and J2, all standard pinouts identify the square pin as pin one.(always!)
Thanks. I missed that the pins were one round one square.
As for the diodes, yes, we have 16 1N4004's with, as noted on the schematic, 1 1N60 sitting there on its own.
Sounds good. (I didn't see the 4004s designated on the schematic, and the 1N60, while on top of that diode, was near the others.)
If I get time, I'll recheck my drawing. It may be that I've missed a wire somewhere...
Just take a quick look at the output wire. Should it be connecte ONLY to R7, or should it also be connected to, say, the + side of C4?
I can't follow your line of thought, but I do know that I have a working 600VA inverter sitting here on my bench, after building according to the above.(It pulls a lot more than 2 amps without any hassles.)
600VA at 120V = 5A RMS. You're only overloading your diodes by a factor of 2.5 from their rating when you max out your inverter, and the diode specs probably allow some slop - especially if they're in a relatively open place in your device, so they can dissipate the heat. (I was assuming something like a 2.5 KVA average, 5 KVA motor-start surge unit.) Even at 2.5A each they're only dissipating about 1.5 watts.
Nevertheless, I'd use five strings of diodes rather than two, to match the rating of the inverter, just to be safe. More for a bigger inverter, of course. 1N4004s are cheap.