I took a look at your last comment to my Diary, and thought I'd take little different tack here.
We've stated the three phase would put out 10.38V at a resistance of 6R, and my design would put out 36V at a resistance of 18R. Let's put some real numbers to this:
Three phase voltage = 20.76 volts, resistance = 1 ohm.
Finnsawyer design/aka Mattson design voltage = 72 volts, resistance = 3 ohms.
We are putting power into a 12 volt battery with two .6 volt diode voltage drops in series.
So, the current into the battery from the three phase is {20.76 - 13.2}/1, or 7.56 amps. The power into the battery is then 90.72 watts.
Similarly, we find the power into the battery with my design would be:
12x(72 - 13.2)/3 = 235.2 watts. Pretty consistent with your results. Now let's assume we rewound the stator (two in hand winding) so that my design puts out 36 volts at .75 ohms resistance. The power into the battery now becomes:
12x(36-13.2)/0.75 = 364.8 watts. Hmm, let's now go to a three in hand winding. The power into the battery becomes:
12x(24-13.2)/0.33 = 392.7 watts. What are we to make of these crazy results? Well, our analysis is only approximate. We should really make the voltages sine waves. So, let's say the three phase voltage goes as 20.76xSINE(wt), while the voltage of my design goes as 72xSINE(3wt). There is a time period when the voltage from my design is less than 13.2 volts. Obviously at wt = 0 we get no voltage. That corresponds to an angle of zero in the cycle of the waveform. Conduction starts when
72xSINE(beta) = 13.2, from which we can find beta:
beta = ARCSINE(13.2/72) = 10.56 degrees. That is, the alternator conducts current from an angle of 10.56 degrees to an angle of 180 - 10.56 = 169.44 degrees during the first half cycle, and has a similar behavior for each half cycle thereafter. For the other two cases we find beta is equal to 21.5 degrees and 33.4 degrees respectively. So, in reality we should be determining the instantaneous current during the time the diodes conduct and multiplying that by the battery voltage to get the instantaneous power, and from that get the average power.
The three phase alternator is not totally immune from this effect, either. Ideally each phase should conduct for one third of a cycle, 120 degrees. In our example the three phase has a maximum or peak voltage of 20.76 volts at wt = 90 degrees. So, that phase should provide voltage in excess of 13.2 volts from an angle of 30 degrees to 150 degrees. It doesn't. The phase voltage doesn't exceed 13.2 volts until wt (beta) is equal to 39.5 degrees.
The upshot is that all the power ratios should be suspect. A more precise analysis is needed. Nevertheless, I feel that my design should still perform better than the three phase having the same magnets and same size coils.