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Author Topic: Expected power output?  (Read 1473 times)

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Aza

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Expected power output?
« on: January 10, 2005, 06:40:23 AM »
Im building a hydro generator using a permanant magnet alternator.  I have 1.5m available head at 700Litres/hr but might be able to bump it up to 3m (sorry about the metric units but i'm Australian and we use the metric system).  Will 1.5m pressure head be adequate to produce around 100+amps? (im using a VERY big alternator with large NdFeB magnets).  Will increasing it to 3m produce any SIGNIFICANT increase in power output?  Sorry if this a lame question.  I know it will be hard to answer without more details about the alternator (still under construction).
« Last Edit: January 10, 2005, 06:40:23 AM by (unknown) »
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pyrocasto

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Re: Expected power output?
« Reply #1 on: January 10, 2005, 12:08:52 AM »
Ok. If you have 700lph, that's 185gph, which = 3gpm. Power = head(ft) x gpm/10.

That means if you bumb it up to 3m of head, I think you can get 3 watts. Half that at 1.5 meaters of head.


I may be wrong, someone correct me if I am.

« Last Edit: January 10, 2005, 12:08:52 AM by pyrocasto »
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luckylogger

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Re: Expected power output?
« Reply #2 on: January 10, 2005, 12:30:00 AM »
check out this page www.energyalternatives.ca hope it helps lots of cool conversion stuff.
« Last Edit: January 10, 2005, 12:30:00 AM by luckylogger »
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Flux

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Re: Expected power output?
« Reply #3 on: January 10, 2005, 01:38:19 AM »
I think you are a bit low, but not far enough out to worry about.


Did you mean 700L/sec Aza


Flux

« Last Edit: January 10, 2005, 01:38:19 AM by Flux »
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Aza

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Re: Expected power output?
« Reply #4 on: January 11, 2005, 08:02:02 PM »


No i really meant 700L/hr (0.194L/sec).  700L/sec is a HUGE flow rate!


Thanx guys for helping me out there.

« Last Edit: January 11, 2005, 08:02:02 PM by Aza »
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Nando

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Re: Expected power output?
« Reply #5 on: February 05, 2005, 07:28:39 PM »
AZA:


1.5 meter * 0.194 liter/sec * 6 = 1.746 watts of power, far from what you need.


The formula to determine the possible available power is head(meters) * liters/sec * 6 = watts.


Regards


Nando

« Last Edit: February 05, 2005, 07:28:39 PM by Nando »
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