I was thinking 6 foot blades.
You are sacrificing no power potential based on weight. The 30 turn stator has an internal resistance of .25 ohm and will reach 13.0 volts @ 300 rpm. That's 23 rpm for every DC volt.
If you use 6 foot blades you'll want to see 700 rpm at least in the higher winds to have a good "match" between your blades and generator. So I'll go over that and explain how that works.
You see above that I know the resistance of my stator and I know how many rpm's this things takes to reach the target cut-in voltage. From that I know the rpm/volt. Hence, at any speed I can tell you what the open voltage is. At 700 rpm we will have 700 / 23 = 30.4 open DC volts.
However, the voltage at your batteries is only going to be 14.5. This is where ohm's law comes in handy. Amps = volts / ohms If we take the difference between the open voltage and loaded voltage and divide it by the resistance, it yields the amps (before line and rectifier losses) from the stator.
So we have (30.4 - 14.5) / .25 = 63.6 amps. 63.6 amps x the 14.5 volts = 922 watts.
Now, this looks like a pretty impressive generator. Right? But generators are not 100% efficient. Part of the input power to them is converted to heat. How much heat? Well, more ohm's law stuff. The heat dissipated in the stator winding is given by the current squared times resistance. 63.62 x .25 = 1,011 watts lost to heat! The total power required to turn this generator at 700 rpm therefore becomes the sum of the actual output at the loaded voltage plus the loss, which is 922 + 1,011 = 1,933 watts input power to the shaft.
Now you go back and look at your blades. A decent set of 6 foot blades running at 6-7 TSR @ 1,100 ft elevation in 30 mph wind can develop around 1,100 watts at the shaft.
So what do we have? We have 1,100 watts available input power on a generator that requires 1,933 input. Not even close. Your poor little 6 foot blades will come up against hard stall and this turbine will be a dead horse with that low resistance stator because the blades can't make enough power to turn it at the required speed.
You can "fix" this by putting some resistance in the line and dissipating power in the resistor, which will cause the turbine generator to run at much higher voltage than the true loaded voltage, hence increasing the power efficiency of the generator by increasing it's operating voltage and reducing the amount of amps coming from the winding. But you will not get any gains into the battery where it really counts with this kludged up "fix".
So in the end, this generator is too powerful for 6 foot blades and it won't work. The 45 turn one with 15 AWG wire is a better "match" to available shaft power.
And that, in a nutshell, is how you match the blade power to the load.
--
Chris