I have tried to determine the winding of this motor. In the third photo one can count the number of magnets and the number of coils for 1/3 of the armature and stator. I counted that there are 10 magnets opposed to 9 coils. So for the whole motor there must be 30 magnets and 27 coils. This difference in magnet number and coil number is made to minimize the peak on the clogging torque.
Now lets focus on 1/3 of the armature so on the 120° part where you have 10 magnets opposed to 9 coils. I assume that three of the coils are of phase U, three are of phase V and three are of phase W and that the sequence of the coils is U1, U2, U3, V1, V2, V3, W1, W2 and W3. The magnets of the north poles are called N1 - N15. The magnets of the south poles are called S1 - S15. The sequence is N1, S1, N2, S2 and so on. Now suppose that the armature has a position such that N1 is just opposite coil U2. This means that S15 and S1 are about opposite to coils U1 and U3. So if coil U2 is wound right hand, coils U1 and U3 must be wound left hand! Only then the voltage generated in these three coils will strengthen each other if the three adjacent coils of one phase are connected in series. It must be possible to confirm this by following the incoming and outgoing wires of three adjacent coils of the same phase.
The armature pole angle is 120° / 10 = 12°, The stator pole angle is 120° / 9 = 13,333°. So there is a difference of 1,333° in between the heart of magnet S15 and the heart of coil U1 and also a difference of 1,333° in between the heart of magnet S1 and coil U3. This difference makes that the voltage generated in the coils U1 and U3 is not exactly in phase to the voltage generated in coil U2. But this isn't a problem as the sum of three identical sinusoidal voltages which are out of phase is again a sinusoidal voltage.
You have the same situation if the armature has rotated that much that now magnet N15 is opposed to coil U2. This means that the armature has rotated over 360° / 15 = 24°. So 24° rotation of the armature corresponds to a phase angle of 360°. So 1,333° rotation of the armature corresponds to a phase angle of 20°. This means that if the phase angle for the coil U2 is zero, there will be a positive phase angle of 20° in between coil U1 and U2 and a negative phase angle of 20° in between coil U2 and U3.
It is easy to prove that there is a phase angle of 120° in between the voltage generated in coil V2 and U2 and also a phase angle of 120° in between the voltage generated in coil W2 and U2. So a 3-phase voltage is generated in between the three bundles of three coils.
For the total winding it must be such that the coils of the other two 120° segments are connected such that similar bundles of the three coils of the same phase are connected in series or in parallel. As I see many wires at the soldering points, I assume that the three bundles of three coils are connected in parallel.
The fact that one has used aluminium in stead of copper means that an aluminium coil with a certain wire length and wire thickness will have a larger resistance than a copper coil with the same wire length and thickness but this doesn't mean that the given motor can't be used as a generator. You only should not expect a high efficiency at high currents.