Hi A,
A couple of questions, and please bear with me, my theoretical knowledge is limited, dated, or both ;>].
I thought with a single-phase, full-wave bridge we would need 4 diodes, but I think in this configuration you are saying that is only six?
The trade off with this arrangement is that the losses are higher? Do the diodes also have to be individually more robust, because if I understand you, they would be subject to full current vs. full current, 2/3 of the time, in a (star) 3-phase bridge, in a given conductor... so the RMS current is only (2/3^.5)= .82*I ?
With a 3-phase, full-wave diode bridge there are two sets of diodes which must be electrically isolated from one another. With this method, I assume there are three? Does this make the build more difficult from your experience?
Thx, ~ks