Hi!
I'm about to start soon my next generator. Already have got magnets.
They are 30mm dia 10mm thick grade N45.
16 poles dual rotor, 12 coils, three phase system.
I calculated the rounds/coil with two different formulaes and got
quite a bit different results.
First i used Hugh's formula.
Turns per phase = 17000 x (System voltage V +1.4) / ( Desired cut in speed RPM) / (Strength of flux in Tesla) /
(total area of magnet face in square inches) = 17000 x 13.4 / 200 / 0.6 / 17.53 = 108 turns per phase.
If you have twelve coils total and thus 4 per phase then you should have 27 turns per coil.
Second i used some other foprmula wich i came across in fieldlines.
N = E / ((B * AM) / P)
N = 13.2/((0.6*0.000706858)0.3) = 13.2/0.001413716 = 9337
Where,
N = Total number of turns (for all coils)
E = Voltage generated at cut in speed (13.2)
B = Magnetic flux in teslas ( 1 tesla = 12,000 guass)
AM = Area of the Magnetic Pole in square meters
P = Period (the time it takes the turbine to complete one rotation)
Using the above formula, 9337 turns of wire are needed.
In the calculations, 0.6 tesla was used for the magnetic field.
Since I have 16 poles and 12 coils, I determined 48 turns are needed per coil.
The turns per coil was found by dividing the total number of turns by the product of the coils and poles.
The formula for this calculation is as follows:
TC = N
(P * C)
Where,
TC = Turns per coil
N = Total number of turns (9337)
P = total number of poles (16)
C = Total number of coils (12)
So wich one goes nearer?
If I have to guess, I would say 27 turns per coil might be closer the truth.
I will built the magnet rotors first and then make a test coil to get the cut in
speed around 200 rpm. So these calculations are kind of useless to me anyway.
It would just be interesting to see wich one comes closer.
I thoght that this time i built the rotors and stator first and test it with
lathe. After that i can decide the blade size. I'm still just guessing here but
i am thinkin of seven footer right now.