Author Topic: Great efficientcy 87%  (Read 864 times)

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PaulM2

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Great efficientcy 87%
« on: July 01, 2005, 11:28:44 PM »
I'm charging a battery bank with solar but when the long cloudy days come I need to top them up with the grid. I hate using my old heavy 10amp car battery charger.(At best 55% eff.)  You can make toast on that when the batteries are low and it's pushing high current. So I found 3 switching adaptor power supplies used for computer printers. The rating label says 18v@2.25a. I loaded down to 13v and got 5.3a. I connect the 3 supplies together in parrellel  and get 17A into the battery bank. I drilled a few holes in the case and put on a computer fan. Works GREAT. Input 120vac@2.1a , output 13v@17a or 252w in ,221w out = 87% efficient. My Morningstar charge regulator holds the volts to 14.3v for my sealed batteries.

« Last Edit: July 01, 2005, 11:28:44 PM by (unknown) »

wdyasq

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Tools
« Reply #1 on: July 01, 2005, 06:55:54 PM »
What instruments did you use to measure input and output?


Ron

« Last Edit: July 01, 2005, 06:55:54 PM by (unknown) »
"I like the Honey, but kill the bees"

pyrocasto

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Re: Tools
« Reply #2 on: July 02, 2005, 12:50:34 AM »
That's what I'm wondering.

« Last Edit: July 02, 2005, 12:50:34 AM by (unknown) »

PaulM2

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Re: Great efficientcy 87%
« Reply #3 on: July 02, 2005, 10:39:19 AM »
I just used a digital multimeter on the ac input and dc output while charging the batteries. Use math to figure the input/output efficiency.
« Last Edit: July 02, 2005, 10:39:19 AM by (unknown) »