Using the 1.5 ohms, the dynamic ohms are = 1.5 * 1.73 = 2.6 ohms
Using a MPPT charger
At 300 RPM suing your data the generated voltage would be 300 RPM * 0.8 V/rpm = 240 V that 3 phase rectified is = 338 volts ( less ripple) lets say 300 volts
If we assume 10 % losses in the generator = 30 volts
Current= 30 / 2.6 ohms = 11.54 Amps
So the delivered Voltage would be 300-30 = 270 volts
Power out = 270 * 11.54 = 3.1 KW
Power dissipated by gen = 30 * 11.54 = 346.2 Watts
If instead of 10 % we assign 15 % losses to the generator then:
- -45 = 255 volts
- v / 2.6 ohms = 17.3 Amps
power out 255 * 17.3 = 4.4 KW
Power dissipated by generator = 45 * 17.3 = 778 watts
SO It is always BEST to close the rotor-stator gap and produce the highest possible voltage to attain the greatest efficiency.
Direct charging ( 1/2 Power Wind Mill) at 300 RPM with 300 volts the power distribution would be 300 - 56 volts = 244 volts to be dissipated by the generator with 2.6 Ohms resistance.
Do you care to calculate the power dissipated by the generator ?.
So the system needs to fly at lower RPM like around 150 RPM.
Nando